Pressure over 1000 ml of a liquid is gradually increased from 1 bar to 1001 bar under adiabatic conditions. If the final volume of the liquid is 990 ml and there is linear variation of volume with pre

Question

Pressure over 1000 ml of a liquid is gradually increased from 1 bar to 1001 bar under adiabatic conditions. If the final volume of the liquid is 990 ml and there is linear variation of volume with pressure, the value of Δ U of the process is (Answer as 'abcd', where a = 1, if Δ U is +ve and a = 2, if Δ U is -ve, and 'bcd' is the magnitude of Δ U, in J)

Answer:

1501.00

Solution:

Adiabatic: Δ U = w_on = -∫ P dV. V is linear in P, so ∫ P dV = P_avgΔ V = 501×(-10) bar ml = -5010 bar ml. Δ U = +5010 bar ml = 5010×0.1 = 501 J (positive). Ans = 1501.

TestHub · Accepted Answer

Adiabatic: Δ U = w on = -∫ P dV. V is linear in P, so ∫ P dV = P avg Δ V = 501×(-10) bar ml = -5010 bar ml. Δ U = +5010 bar ml = 5010×0.1 = 501 J (positive). Ans = 1501.

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