When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is J . [nearest integer ] (Given : R = 8 . 3 J K - 1 mol - 1 an

Question

When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is J . [nearest integer ] (Given : R = 8 . 3 J K - 1 mol - 1 and log 2 = 0 . 3010 )

TestHub · Accepted Answer

Work done in isothermal reversible process is calculated by the equation

$W = - 2.303 nRTlog (\frac{V_{2}}{V_{1}}) n = Number of moles T = Temperature = 300 K V_{2} = Final volume = 20 litres V_{1} = Initial volume = 10 litres$

W $= - 2.303 \times 5 \times 8.3 \times 300 \log (\frac{20}{10})$

$= - 8630.38 J$

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