Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IDH/DU for reactionMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
An amount of 3 mole of nitrogen gas is taken in a rigid vessel at 27°C and 1 atm and the vessel is sealed. Now the gas is heated to 107°C. (Take R = 2 cal/mol K; treat N2 as an ideal diatomic gas.)
What is the change in enthalpy of the gas?
Options:
Answer:
B
Solution:
Cp,m = 7/2R = 7 cal/mol K. Δ H = nCp,mΔ T = 3 × 7 × 80 = 1680 cal (equivalently Δ U + nRΔ T = 1200 + 480). Matches (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:DH/DU for reaction
⏱ 2mℹ️ Source: QB
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