Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsHard2 minQB
ChemistryHardnumerical
The internal energy of a monoatomic ideal gas is 1.5 nRT. One mole of helium is kept in a cylinder of cross section 8.5 cm2. The cylinder is closed by a light frictionless piston. The gas is heated slowly in a process during which a total of 42 J heat is given to the gas. If the temperature rises through 2°C, find the distance moved by the piston (in cm). Atmospheric pressure = 100 kPa.
Answer:
20.00
Solution:
Δ U = 1.5×8.314×2 = 24.9 J. w = q - Δ U = 42 - 24.9 = 17.1 J. Constant external pressure: w = PA d, PA = 105×8.5×10-4 = 85 N. d = 17.1/85 = 0.201 m ≈ 20 cm. Ans = 0020.
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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