Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricMedium2 minQB

ChemistryMediummultiple choice

Passage / Comprehension

2 moles of an ideal gas are subjected to two different processes (separately).

Process A: $(2 ba r, 300 K)$ to $(2 ba r, 450 K)$ isobarically.

Process B: $(30 l i t re, 300 K)$ to $(30 l i t re, 450 K)$ isochorically.

Given: $C_{v, m} = \frac{3}{2} R$

$R = 2 c a l / m o l - K$

Which of the following in CORRECT for process A

Answer:

A, B, D

Solution:

For an isobaric process, $T$ increases from $300 K$ to $450 K$ , so $Δ T = 150 K$ .

Using ideal gas relations, $Δ U = n C_{V} Δ T$ and $Δ H = n C_{P} Δ T$ .

Here $C_{V} = \frac{3}{2} R$ and $C_{P} = \frac{5}{2} R$ , so both $Δ U$ and $Δ H$ are directly proportional to $Δ T$ .

Also, the work done $W = n R Δ T$ for an isobaric process.

On calculation (with given data in exam units), all three results match options A, B, and D.

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric

⏱ 2mℹ️ Source: QB

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