Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
An ideal gas whose adiabatic exponent equals γ is expanded according to the law P = α V, where α is a constant. The initial volume of the gas is equal to V0. As a result of expansion, the volume increases 4 times.
What is the increment of the internal energy of the gas?
Options:
Answer:
A
Solution:
Δ U = nCvΔ T = (Δ(PV))/(γ-1). Initially P1V1 = α V02; finally V2 = 4V0, P2V2 = α(4V0)2 = 16α V02. Δ U = ((16-1)α V02)/(γ-1) = (15α V02)/(γ-1). Matches (a).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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