Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IIsothermal Process/Isobaric/IsochoricMedium2 minQB
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A piston can freely move inside a horizontal cylinder closed from both ends. Initially, the piston separates the inside space of the cylinder into two equal parts each of volume Vo, in which an ideal gas is contained under the same pressure Po and at the same temperature. What work has to be performed in order to increase isothermally the volume of one part of gas η times compared to that of the other by slowly moving the piston?

Options:

Answer:
B
Solution:

Final volumes: Va = η Vb and Va + Vb = 2Vo, so Vb = (2Vo)/(1+η), Va = (2η Vo)/(1+η). Work done on the gases (both isothermal, nRT = PoVo for each part) = -PoVo[ln(Va)/(Vo) + ln(Vb)/(Vo)] = -PoVoln(4η)/((1+η)2) = PoVoln((η+1)2)/(4η). Matches (b).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Isothermal Process/Isobaric/Isochoric
⏱ 2mℹ️ Source: QB

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