Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IFirst law of ThermodynamicsHard2 minQB
ChemistryHardsingle choice
Passage / Comprehension
An ideal gas whose adiabatic exponent equals γ is expanded according to the law P = α V2, where α is a constant. The initial volume of the gas is equal to V0. As a result of expansion, the volume doubles.
What is the increment of the internal energy of the gas?
Options:
Answer:
B
Solution:
Δ U = (Δ(PV))/(γ-1). PV = α V3. Initially α V03; finally α(2V0)3 = 8α V03. Δ U = ((8-1)α V03)/(γ-1) = (7α V03)/(γ-1). Matches (b).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: QB
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