One mole of an ideal gas expands isothermally and reversibly from $10 dm^{3}$ to $20 dm^{3}$ at $300 K .Δ U$ , q and work done in the process respectively are :
Given : $R = 8.3 JK^{- 1}$ and $mol^{- 1}$
$In 10 = 2.3 lo g 2 = 0.30 lo g 3 = 0.48$

Question

TestHub · Accepted Answer

​ ( 10 L , 300 K ) n = 1 ​ ( 20 L , 300 K ) − q = w = − nRT ln V 1 ​ V 2 ​ ​ = − 8.3 × 300 × ln ( 10 20 ​ ) = − 1.718 kJ ⇒ q = 1.718 kJ w = − 1.718 kJ Δ U = 0 ( ∵ Δ T = 0 ) ​

Chemistry - Thermodynamics - I Question with Solution | TestHub

Options:

Doubts & Discussion