Start Free Mock LoginAlready registered? Login here

Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minPYQ_2024

ChemistryMediummatching list

If $5$ moles of an ideal gas expands from $10 L$ to a volume of $100 L$ at $300 K$ under isothermal and reversible condition then work, $w$ , is $- x J$ . The value of $x$ is $-$ _______.

(Given $R = 8 .314 J K^{- 1} {mol}^{- 1}$ )

Answer:

-28721

Solution:

Given,

$T = 300 K, V_{1} = 10 L, V_{2} = 100 L, n = 5$

It is isothermal reversible expansion, so work done negative

$W = - 2 .303 nRT \log (\frac{V_{2}}{V_{1}})$

$= - 2 .303 \times 5 \times 8 .314 \times 300 \log (\frac{100}{10})$

$= - 28720 .713 J$

$\equiv - 28721 J$

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...