Chemistry - Thermodynamics - I Question with Solution | TestHub

The quality of heat absorbed by the gas,$\mathrm{Q}=\mathrm{\Delta }\mathrm{E}+\mathrm{W},$here W is the work done by the gas. For free expansion i.e., expansion against vacuum,$\mathrm{W}=0$; at constant temperature , the internal energy of an ideal gas is constant and so$\mathrm{\Delta }\mathrm{E}=0$. Thus$\mathrm{Q}=0$.