Chemistry - Thermodynamics - I Question with Solution | TestHub

By applying the Helmholtz equation: it shows the relationship between $\mathrm{Change} \mathrm{in} \mathrm{enthalpy} \left(∆\mathrm{H}\right), \mathrm{change} \mathrm{in} \mathrm{entropy}\left(∆\mathrm{S}\right) \& \mathrm{change} \mathrm{in} \mathrm{free} \mathrm{energy}\left(∆\mathrm{G}\right)$

$∆\mathrm{G} = ∆\mathrm{H} -\mathrm{T}∆\mathrm{S}$

For spontaneous reaction 

$∆\mathrm{G} = -\mathrm{Ve} , ∆\mathrm{S} = +\mathrm{Ve} \mathrm{and} ∆\mathrm{H} = -\mathrm{Ve}$