Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IHeat & Heat CapacityEasy2 minQB
ChemistryEasysingle choice
What is the heat capacity of the ideal monoatomic gas undergoing the process shown in the figure?
Options:
Answer:
C
Solution:
The tangent at the point (V = 2 L, P = 4 atm) makes 45° with the V axis, so |dP/dV| = 1 atm/L (equal axis scales). For PVx = constant, dP/dV = -xP/V, so 1 = x × 4/2 and x = 0.5. C = CV + R/(1-x) = 1.5R + 2R = 3.5R. Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Heat & Heat Capacity
⏱ 2mℹ️ Source: QB
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