The temperature coefficient of a cell whose cell reaction is P b ( s ) + H g C l 2 ( a q ) → P b C l 2 ( a q ) + H g ( l ) d E d T P = 1.5 × 1 0 - 4 V K - 1 at 298 The change in entropy for the given cell reaction will be

d E d T P = Δ S n F 1.5 × 1 0 - 4 = Δ S 2 × 96500 Δ S = 28.95 J K - 1 m o l - 1 .

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Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020

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The temperature coefficient of a cell whose cell reaction is
$P b (s) + H g C l_{2} (a q) \to P b C l_{2} (a q) + H g (l)$
${(\frac{d E}{d T})}_{P} = 1.5 \times 1 0^{- 4} V K^{- 1}$ at 298
The change in entropy for the given cell reaction will be

Options:

Answer:

Solution:

${(\frac{d E}{d T})}_{P} = \frac{Δ S}{n F}$
$1.5 \times 1 0^{- 4} = \frac{Δ S}{2 \times 96500}$
$Δ S = 28.95 J K^{- 1} m o l^{- 1}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2020

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