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Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minPYQ_2019

ChemistryMediumsingle choice

The work done in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to 20 litres at $2 5^{\circ} C$ is

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Answer:

Solution:

$W = 2.303 nRT lo g \frac{V _{2}}{V _{1}} = 2.303 \times 1 \times 8.314 \times 1 0^{7} \times 298 lo g \frac{20}{10} = 298 \times 1 0^{7} \times 8.31 \times 2.303 lo g 2$

Stream:VITEEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2019

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