The difference between the reaction enthalpy change ( Δ r H ) and reaction internal energy change ( Δ r U ) for the reaction: 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ at 300 K is ( R = 8.314 J mol −

Question

The difference between the reaction enthalpy change ( Δ r ​ H ) and reaction internal energy change ( Δ r ​ U ) for the reaction: 2 C 6 ​ H 6 ​ ( l ) + 15 O 2 ​ ( g ) ⟶ at 300 K is ( R = 8.314 J mol − 1 K − 1 )

TestHub · Accepted Answer

Δ H = Δ U + Δ n g ​ RT For the reaction Δ n g ​ = 12 − 15 = − 3 Δ H − Δ U ​ = − 3 × 8.314 × 300 = − 7482 J mol − 1 ​

Chemistry - Thermodynamics - I Question with Solution | TestHub

Options:

Doubts & Discussion