Chemistry - Thermodynamics - I Question with Solution | TestHub

The molar heat capacity for any process is given by a following expression $C=C_V+\frac{R}{1-\gamma }$ when $p{V}^{\gamma }=$ constant and $C_p/C_V=\gamma$ Here, $\frac{p}{V}=1$ i.e., $p{V}^{-1}=$ constant $$\therefore C=\frac{3}{2}R+\frac{R}{1-(-1)}=\frac{3}{2}R+\frac{R}{2}=\frac{4}{2}R$$