A gas is expanded from volume V 0 to 2 V 0 under three different process. Process 1 is isobaric, process 2 is isothermal and process 3 is adiabatic. Let Δ U 1 , Δ U 2 and Δ U 3 be the change

Question

A gas is expanded from volume V 0 ​ to 2 V 0 ​ under three different process. Process 1 is isobaric, process 2 is isothermal and process 3 is adiabatic. Let Δ U 1 ​ , Δ U 2 ​ and Δ U 3 ​ be the change in internal energy of the gas in these three processes. Then :

TestHub · Accepted Answer

Question Explanation:

The question asks about the order of $Δ U$ .

Concept:

This question is based on a comparison of adiabatic and isothermal processes.

Solution:

Process I: $P =$ constant.

Therefore, $T$ will increase with volume.

$∴ Δ U_{1} = + v e$

Process II: $Δ T = 0$

$∴ Δ U_{2} = 0$

Process III:

During adiabatic expansion,

$Δ T = - v e$

$Δ U_{3} = - v e$

Final Answer: Option (A)

Chemistry - Thermodynamics - I Question with Solution | TestHub

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