Chemistry - Thermodynamics - 1 Question with Solution | TestHub

ChemistryThermodynamics - 1Adiabatic Process/PolytropicEasy2 minPYQ_2020

ChemistryEasysingle choice

A gas is allowed to expand at constant temperature from a volume of 1.0 L to 10.1 L against an external pressure of 0.50 atm. If the gas absorbs 250 J of heat from the surroundings, what are the values of q, w and $Δ E$ ? (Given 1 L atm = 101.0 J)

Options:

Answer:

Solution:

Since heat is absorbed, $q = + 250 J$

Work done $= - p (V_{2} - V_{1})$

$= - 50 atm \times (10.1 L - 1.0 L)$

$= - 0.50 atm \times 9.1 L$

$= - 0.50 \times 9.1 L atm \times \frac{101.0 J}{1 L atm} =- 460.0 J$

Also $Δ E = q + w = 250 J - 460 J = - 210 J$

Stream:NTA_ABHYASSubject:ChemistryTopic:Thermodynamics - 1Subtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

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q	w	$Δ E$
-250 J	- 460 J	- 710 J