A gas expands adiabatically at constant pressure such that T ∝ 1 V The value of γ , i.e., C P C V of the gas will be

T ∝ 1 V T V 1 2 = constant For adiabatic process, T V 1 2 = T V γ - 1 = constant So γ - 1 = 1 2 γ = 3 2 .

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ChemistryThermodynamics - 1Adiabatic Process/PolytropicEasy2 minPYQ_2020

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A gas expands adiabatically at constant pressure such that

$T \propto \frac{1}{\sqrt{V}}$

The value of $γ$ , i.e., $(\frac{C_{P}}{C_{V}})$ of the gas will be

Options:

Answer:

Solution:

$T \propto \frac{1}{\sqrt{V}}$

$T V^{\frac{1}{2}} =$ constant

For adiabatic process, $T V^{\frac{1}{2}} = T V^{γ - 1} =$ constant

So $γ - 1 = \frac{1}{2}$

$γ = \frac{3}{2}$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Thermodynamics - 1Subtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: PYQ_2020

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