Chemistry - Thermodynamics - 1 Question with Solution | TestHub

When the following reaction was carried out in a bomb calorimeter,$\mathrm{\Delta }\mathrm{U}$is found to be$-\text{740}\text{.0}\text{kJ/mol}$of${\text{NH}}_{\text{2}}\text{CN(s)}$(s) at$\text{300}\text{K}$.
$\mathrm{N}{\mathrm{H}}_2\mathrm{C}{\mathrm{N}}_{\left(\mathrm{s}\right)}+\mathrm{ }\frac{3}{2}{\mathrm{O}}_{2\left(\mathrm{g}\right)}\to {\mathrm{N}}_{2\left(\mathrm{g}\right)}+\mathrm{ }\mathrm{C}{\mathrm{O}}_{2\left(\mathrm{g}\right)}+\mathrm{ }{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}$
Calculate${\text{ΔH}}_{\text{300}\text{K}}$for the reaction.