Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB
ChemistryMediumstatement
Statement 1: The magnitude of enthalpy of combustion of diamond is greater than that of graphite.
Statement 2: Graphite is thermodynamically more stable form of carbon than diamond.
Options:
Answer:
A
Solution:
Graphite is the thermodynamically stable allotrope of carbon (Statement 2 is correct); thus, diamond has a higher enthalpy by approximately 2 kJ/mol. The combustion of either allotrope yields the same product, CO₂ (g). Consequently, the higher-enthalpy diamond releases more heat upon combustion: |Δc H(diamond)| > |Δc H(graphite)| (Statement 1 is correct). The increased stability of graphite directly explains why diamond combustion releases more heat.
The final answer is (a).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB
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