Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryBorn Haber CycleMedium2 minQB
ChemistryMediumnumerical

For an ionic solid , where X is monovalent, the enthalpy of formation of the solid from M(s) and is 1.5 times the electron gain enthalpy of X(g). The first and second ionisation enthalpies of the metal (M) are 1.2 and 2.8 times of the enthalpy of sublimation of M(s). The bond dissociation enthalpy of is 0.8 times the first ionisation enthalpy of metal and it is also equal to one-fifth of the magnitude of lattice enthalpy of . If the electron gain enthalpy of X(g) is -96Kcal/mol , the answer the enthalpy of sublimation of metal (M) in Kcal/mol.

Answer:
41.38
Solution:

Born-Haber Cycle Formula:

 

Given Values:

 

Expressing Terms via Sublimation Energy (): , , and

 

Lattice Enthalpy:

 

Substitution & Calculation:

 

Final Solution:

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Born Haber Cycle
2mℹ️ Source: QB

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