Solution I: 1 mole of H 2 SO 4 dissolved in 5 moles of water.

Chemistry - Thermochemistry Question with Solution | TestHub

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Passage / Comprehension

The integral enthalpy of solution of one mole of H₂SO₄ in n mole of water is given by the equation ΔH = -75n/(n+1.8) kJ/mol. Determine ΔH for the following solutions:

Solution I: 1 mole of H₂SO₄ dissolved in 5 moles of water.

Options:

Answer:

Solution:

For n = 5, the change in enthalpy (Δ H) is calculated as follows:

Δ H = (-75(5))/(5 + 1.8) = (-375)/6.8 = -55.15 kJ

The correct answer is (d).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of solution/dilution/hydration

⏱ 2mℹ️ Source: QB

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