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ChemistryThermochemistryEnthalpy of ReactionMedium2 minQB
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Determine the standard enthalpy of reaction: C4H10(g) + H2(g) → 2C2H6(g), using the given enthalpies of combustion under standard conditions:

Compound | H2(g) | C2H6(g) | C (graphite)

ΔH° (kJ/mol) | -285.8 | -1560.0 | -393.5

The standard enthalpy of formation of C4H10(g) is -126.1 kJ/mol

Options:

Answer:
C
Solution:

Δf H(C2H6) = 2(-393.5) + 3(-285.8) - (-1560.0) = -787.0 - 857.4 + 1560.0 = -84.4 kJ. ΔH = 2(-84.4) - [(-126.1) + 0] = -168.8 + 126.1 = -42.7 kJ. This is option (c).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: QB

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