Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of CombustionHard2 minQB
ChemistryHardsingle choice

The enthalpies of combustion of acetaldehyde and paraldehyde (a polymer of acetaldehyde) are -1167 and -3477 kJ/mol, respectively. The enthalpy of polymerization per mole of paraldehyde is -24 kJ. The molecular formula of paraldehyde is

Options:

Answer:
C
Solution:

Cycle: 1 mol paraldehyde → n mol CH3CHO (depolymerization, ΔH = +24 kJ) → combustion of n mol CH3CHO (-1167n kJ). Equating with direct combustion: -3477 = 24 - 1167n, so n = 3501/1167 = 3. Formula (C2H4O)3 = C6H12O3. This is option (c).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB

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