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ChemistryThermochemistryBorn Haber CycleMedium2 minQB
ChemistryMediumnumerical
Passage / Comprehension

Born-Haber cycle is extensively used to calculate Lattice enthalpy using various other enthalpies such as Ionization enthalpy, Electron gain enthalpy , Formation enthalpy, Sublimation enthalpy etc. Consider the following Born-Haber cycle.

Number of compounds having MORE magnitude of lattice enthalpy (magnitude) compared to CsF among CsI , LiF, RbF , KF, CsBr, CsCl , is

Answer:
3.00
Solution:

Lattice enthalpy magnitude is inversely proportional to the sum of ionic radii () because all the compared compounds have the same ionic charges ( and ). CsF consists of the largest alkali metal cation (Cs⁺) and the smallest halide anion (F⁻). Among the given fluorides (LiF, KF, RbF), the smaller cations decrease the interionic distance, resulting in a higher magnitude of lattice enthalpy than CsF. Conversely, in the cesium halides (CsCl, CsBr, CsI), the larger anions increase the distance, lowering the lattice enthalpy. Therefore, exactly 3 compounds (LiF, KF, and RbF) have a greater magnitude of lattice enthalpy than CsF.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Born Haber Cycle
2mℹ️ Source: QB

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