Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of ReactionMedium2 minQB
ChemistryMediumsingle choice
In cells with plentiful O2, fructose is oxidized completely to CO2 and H2O (aerobic oxidation). When deprived of O2, one molecule of fructose is converted to two molecules of lactic acid (anaerobic glycolysis).
C6H12O6(fructose, s) + 6O2(g) → 6CO2(g) + 6H2O(l); ΔH° = -2810 kJ/mol
C6H12O6(fructose, s) → 2CH3CH(OH)COOH(s); ΔH° = +2400 kJ/mol
Which statement is true with respect to energy change as heat?
Options:
Answer:
C
Solution:
Advantage of aerobic oxidation = ΔHglycolysis - ΔHaerobic = +2400 - (-2810) = 5210 kJ/mol of extra energy released per mole of fructose. Aerobic oxidation has the advantage by 5210 kJ/mol, option (c).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: QB
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