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ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

Enthalpy of $C H_{4} + \frac{1}{2} O_{2} \to C H_{3} O H$ is negative. If enthalpy of combustion of $C H_{4}$ and $C H_{3} O H$ are x and y respectively, which relation is correct?

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Answer:

Solution:

Enthalpy of combustion is -ve (exothermic) $C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O; Δ H = - x$
$C H_{3} O H + \frac{3}{2} O_{2} \to C O_{2} + 2 H_{2} O; Δ H = - y$
$C H_{4} + \frac{1}{2} O_{2} \to C H_{3} O H; Δ H = y - x$
As $y - x = - v e$
So $x > y$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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