When 100 ml of 1 M H 3 PO 3 is neutralized completely by 1 M NaOH the heat liberated is 10.668 KJ . If enthalpy of neutralization of HCl by NaOH is − 55.84 KJ mol − 1 . The Δ Hionization of H 3

Question

When 100 ml of 1 M H 3 ​ PO 3 ​ is neutralized completely by 1 M NaOH the heat liberated is 10.668 KJ . If enthalpy of neutralization of HCl by NaOH is − 55.84 KJ mol − 1 . The Δ Hionization of H 3 ​ PO 3 ​ is ____ KJ/mole.

TestHub · Accepted Answer

H 3 ​ PO 3 ​ → 2 H + + HPO 3 ​ ; Δ H r ​ = ? 2 H + + 2 OH − → 2 H 2 ​ O Δ H r ​ = − 55.84 × 2 = − 111.68 Heat of neutralization of H 3 ​ PO 3 ​ is 10 × 10.668 − 106.68 = Δ H ion ​ − 111.68Δ H ion ​ − 5 KJ / mole . ​

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