Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryMiscelleneous EnthalpiesHard2 minQB
ChemistryHardsingle choice
The strain energy (in kJ/mol) of cyclobutane from the following data:
Δf H [C4H8(g)] = 28.0 kJ/mol; Δf H [C(g)] = 715.0 kJ/mol; Δf H [H(g)] = 218.0 kJ/mol
BE (C-C) = 348.0 kJ/mol; BE (C-H) = 412.0 kJ/mol.
Options:
Answer:
A
Solution:
Unstrained cyclobutane (4 C–C, 8 C–H): To atomize 4C(s) + 4H₂ (g), the energy required is 4(715) + 8(218) = 4604 kJ. The energy released when bonds are formed is 4(348) + 8(412) = 4688 kJ. Therefore, the enthalpy of formation for unstrained cyclobutane is Δf H(unstrained) = 4604 - 4688 = -84 kJ/mol.
The strain energy is calculated as 28 - (-84) = 112 kJ/mol. This corresponds to option (a).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Miscelleneous Enthalpies
⏱ 2mℹ️ Source: QB
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