Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of ReactionHard2 minQB
ChemistryHardsingle choice
Passage / Comprehension
For the reaction at 25°C, Y2O4(l) → 2YO2(g), Δ E° = 2.1 kcal and ΔS° = 8 cal/K.
The reaction at 25°C is
Options:
Answer:
D
Solution:
The positive standard Gibbs free energy change, ΔG° = +0.91 kcal, indicates that the reaction is non-spontaneous under standard conditions and is endergonic.
It is important to note that a positive standard cell potential (Δ E° > 0) and a positive standard entropy change (ΔS°) do not guarantee spontaneity at 298 K. In this case, the TΔS term, which is 2.38 kcal, is smaller than the enthalpy change ΔH = 3.29 kcal. This corresponds to option (d).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: QB
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