Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryHess's Law of Constant Heat SummationEasy2 minQB
ChemistryEasynumerical

The heat of total cracking of hydrocarbons, ΔHTC is defined as ΔH at 298.15 K and 101.325 kPa for the process:

CnHm + (2n - m/2)H2(g) → nCH4(g)

The values of ΔHTC is -68.0 kJ for C2H6 and -95.0 kJ for C3H8. Calculate ΔH (in kJ) for

CH4(g) + C3H8(g) → 2C2H6(g)

Answer:
41.00
Solution:

C2H6 + H2 → 2CH4, ΔH = -68.0 kJ; C3H8 + 2H2 → 3CH4, ΔH = -95.0 kJ. Target = (second) - 2×(first): ΔH = -95.0 - 2(-68.0) = +41 kJ. Answer: 0041.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Hess's Law of Constant Heat Summation
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...