The enthalpy change involved in the oxidation of glucose is – 2880 k J m o l - 1 . Twenty five percent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one k

Question

The enthalpy change involved in the oxidation of glucose is – 2880 k J m o l - 1 . Twenty five percent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometer, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?

TestHub · Accepted Answer

Total energy involved in the oxidation of glucose $= - 2880$ $k J m o l^{- 1}$ .
As twenty five percent of this energy is available for muscular work.
So energy available for muscular work $= \frac{2880 \times 25}{100} = 720$ $k J m o l^{- 1}$
Energy available for muscular work from 120 g glucose $= \frac{720 \times W_{g l u c o s e}}{m o l e c u l a r w e i g h t} = \frac{720 \times 120}{180} = 480 k J$
As 100 kJ energy is enough for = 1 km
so 480 kJ energy is enough for $= \frac{480 \times 1}{100} = 4.8 k m$

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