Chemistry - Thermochemistry Question with Solution | TestHub
A factory is producing methanol based on the reaction:
CO + 2H2 → CH3OH; ΔH = -120 R
Hydrogen and carbon monoxide are obtained by the reaction:
CH4 + H2O → CO + 3H2
Three units of factory, namely, reformer (for the production of H2 and CO), reactor (for the production of methanol from CO and H2) and separator (to separate CH3OH from CO and H2) are schematically shown in the figure:
The flow of methanol from Valve-3 is 600 mol/sec. The factory is so designed that 3/4 of the CO is converted to CH3OH. Assume that the reformer reaction goes to completion and R = 2 cal/K-mol.
What is the flow of CO and H2 at valve-1?
Options:
Answer:
Solution:
CH3OH out = 600 mol/s is 3/4 of the CO fed, so CO at valve-1 = 600×4/3 = 800 mol/s. The reformer gives CO : H2 = 1 : 3, so H2 = 3×800 = 2400 mol/s. This is option (d).
