Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB

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Passage / Comprehension

3.2 g of methane was subjected to combustion at 27° C in a Bomb Calorimeter. The temperature of

calorimeter system (including water) was found to rise by 0.8° C. The thermal capacity of calorimeter system

is 25 kJ K^-1. (R = 8 J mol^-1K^-1 )

The heat of combustion of methane at constant volume is : (in $kJ / mol$ )

Answer:

Solution:

$q_{v} = \frac{25 \times 0.8 \times 16}{3.2} = 100 kJ /$ mole (released heat at constant volume)

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion

⏱ 2mℹ️ Source: QB

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