Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryMiscelleneous EnthalpiesEasy2 minQB
ChemistryEasymatching list
Match the columns
Column I | Column II |
|---|---|
P) Na(s) → Na(g) | i) ΔHcombustion |
Q) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) | ii) ΔHneutralization |
R) HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) | iii) ΔHatomization |
S) C (graphite) + 2H2(g) → CH4(g) | iv) ΔHformation |
(Column I = Reaction; Column II = Δr H is also known as)
Options:
Answer:
B
Solution:
P: Converting solid sodium to gaseous Na atoms is the atomization (sublimation) of the metal, P-iii.
Q: Burning methane completely is combustion (nothing is formed from elements here), Q-i.
R: The reaction of a strong acid plus a strong base to form salt and water is neutralization, R-ii.
S: The formation of 1 mol of CH₄ from graphite and H₂, which are the standard states of its elements, is the formation of methane, S-iv.
Answer: P-iii; Q-i; R-ii; S-iv.
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Miscelleneous Enthalpies
⏱ 2mℹ️ Source: QB
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