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ChemistryThermochemistryMiscelleneous EnthalpiesMedium2 minQB
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The molar heat capacities of liquid benzene and benzene vapour are 136 and 82 J/mol-K, respectively. If the enthalpy of vaporization of benzene is 31.0 kJ/mol at 80°C, the enthalpy of vaporization at 100°C should be about

Options:

Answer:
D
Solution:

ΔHvap(100) = ΔHvap(80) + [CP(g) - CP(l)] ΔT = 31.0 + (82 - 136)(20)/1000 = 31.0 - 1.08 = 29.9 kJ/mol. This is option (d).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Miscelleneous Enthalpies
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