Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
When 12 g of carbon reacted with oxygen to form CO and CO2 at 298 K and constant pressure, 53.2 kcal of heat was liberated and no carbon remained. Heat of formation of CO and CO2 are -26.0 and -94.0 kcal/mole, respectively.
Moles of CO formed is
Options:
Answer:
C
Solution:
Given 12 g of carbon, which is 1 mol.
Let the moles of CO be x and the moles of CO₂ be 1 - x.
The total heat produced is calculated as:
26x + 94(1-x) = 53.2
26x + 94 - 94x = 53.2
94 - 68x = 53.2
68x = 94 - 53.2
68x = 40.8
x = 40.8/68
x = 0.6 mol
Therefore, the moles of CO are 0.6 mol. This corresponds to option (c).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB
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