Chemistry - Thermochemistry Question with Solution | TestHub

Enthalpy of formation of ${\mathrm{C}}_2{\mathrm{H}}_4,{\mathrm{CO}}_2$ and ${\mathrm{H}}_2\mathrm{O}$ are $52,-394$ and $-286\mathrm{kJ}/\mathrm{mol}$ respectively.
(Given)
The reaction is
${\mathrm{C}}_2{\mathrm{H}}_4+3{\mathrm{O}}_2\to 2{\mathrm{CO}}_2+2{\mathrm{H}}_2\mathrm{O}$
change in enthalpy,
$(\Delta H)=\Delta H_{\text{products }}-\Delta H_{\text{reactants }}$
$=2\times (-394)+2\times (-286)-(52+0)$
$=-1412\mathrm{kJ}/\mathrm{mol}$.