IfC(s) + O 2 ( g ) ⟶ CO 2 ( g ) ; Δ H = R and CO ( g ) + 2 1 O 2 ( g ) ⟶ CO 2 ( g ) ; Δ H = S , then heat of formation of CO is:

Let, C ( s ) + O 2 ( g ) ⟶ CO 2 ( g ) ; Δ H = R and CO ( g ) + 2 1 O 2 ( g ) ⟶ CO 2 ( g ) ; Δ H = S (ii) Subtrācting ęu. (i) from èu (ii), wê get C ( s ) + 2 1 O 2 ( g ) ⟶ CO ( g ) ; Δ H = R − S Hence, heat of formation of CO = R − S

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionHard2 minPYQ_2021

ChemistryHardsingle choice

IfC(s) $+ O_{2} (g) ⟶ CO_{2} (g); Δ H = R$ and $CO (g) + \frac{1}{2} O_{2} (g) ⟶ CO_{2} (g); Δ H = S$ , then heat of formation of $CO$ is:

Options:

Answer:

Solution:

Let, $C (s) + O_{2} (g) ⟶ CO_{2} (g); Δ H = R$ and $CO (g) + \frac{1}{2} O_{2} (g) ⟶ CO_{2} (g); Δ H = S$ (ii) Subtrācting ęu. (i) from èu (ii), wê get $C (s) + \frac{1}{2} O_{2} (g) ⟶ CO (g); Δ H = R - S$ Hence, heat of formation of $CO = R - S$

Stream:VITEEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...