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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

The heat of solution of one mole of $N a_{2} S O_{4} . 10 H_{2} O$ is -78.7 kJ, and that of dehydration, -81.6 kJ. The heat of solution (kJ) of anhydrous sodium sulphate is

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Answer:

Solution:

From Hess's law, $Q = - (- 81.6 kJ) + (- 78.7 kJ)$
$= 81.6 kJ - 78.7 kJ = + 2.9 kJ$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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