Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020
ChemistryEasysingle choice

Given:

C graphite + O 2 g → CO 2 g  ; Δ r H o =−393.5  kJ mol −1

H2g+12O2g→H2Ol;ΔrHo=-285.8 kJ mol-1

CO2g+2H2Ol→CH4g+2O2g;ΔrHo=+890.3 kJ mol-1

Based on the above thermochemical equations, the value ofΔrHoat 298 K for the reaction

Cgraphite+2H2g→CH4gwill be:

Options:

Answer:
B
Solution:

For reaction

CO 2 (g)+2H 2 O(l)→ CH 4 (g)+2O 2 (g)

ΔrHo=ΣΔfHoproducts-ΣΔfHoreactants

=ΔrHoCH4+2×0-ΔfHoCO2+2ΔfHoH2O

+890.3=ΔfHoCH4--393.5+2×-285.8

Δ f H o of CH 4  (g)=−74.8 kJ/mol

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: PYQ_2020

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