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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2020

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Lattice enthalpy and enthalpy of solution of $NaCl$ are $788 {kJmol}^{- 1}$ and $4 k J m o l^{- 1}$ , respectively. The hydration enthalpy of $N a C l$ is:

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Answer:

Solution:

Enthalpy of solution= Lattice enthalpy + enthalpy of hydration

$4 = 788 + ∆ H_{hydration} \Rightarrow ∆ H_{hydration} = - 784 KJ / mol$

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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