Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryAdiabatic Process/PolytropicMedium2 minPYQ_2020
ChemistryMediumsingle choice

The combustion of benzenelgivesCO2gandH2Ol. Given that heat of combustion of benzene at constant volume is-3263.9 kJmol-1heat of combustion (in kJmol-1) of benzene at constant pressure will be

R=8.314JK-1mol-1

Options:

Answer:
A
Solution:

C6H6l+152O2g6CO2g+3H2Ol

Δng=6-152=-32

ΔH=ΔU+ΔngRT

ΔH=-3263900-32×8.314×298J

      =-3267616 J

      =-3267.616 kJ

Stream:NTA_ABHYASSubject:ChemistryTopic:ThermochemistrySubtopic:Adiabatic Process/Polytropic
2mℹ️ Source: PYQ_2020

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