Calculate enthalpy change for the change 8 S ( g ) ⟶ S 8 ( g ) , given that H 2 S 2 ( g ) ⟶ 2 H ( g ) + 2 S ( g ) , Δ H = 239.0 k cal mol − 1 H 2 S ( g ) ⟶ 2 H ( g ) + S ( g ) , Δ H = 175.0 kc

Question

Calculate enthalpy change for the change 8 S ( g ) ⟶ S 8 ​ ( g ) , given that H 2 ​ S 2 ​ ( g ) ⟶ 2 H ( g ) + 2 S ( g ) , Δ H = 239.0 k cal mol − 1 H 2 ​ S ( g ) ⟶ 2 H ( g ) + S ( g ) , Δ H = 175.0 kcal mol − 1 ​

TestHub · Accepted Answer

Δ H S − S ​ + 2Δ H H − S ​ = 239 2Δ H H − S ​ = 175 ​ Hence, Δ H S − S ​ = 239 − 175 = 64 kcal mol − 1 Then, Δ H for 8 S ( g ) ​ → S 8 ( g ) ​ is 8 × ( − 64 ) = − 512 kcal

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