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ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2018
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The combustion of benzenelgivesCO2gandH2Ol.Given that heat of combustion of benzene at constant volume is-3263.9 kJ mol-1at25°C;the heat of combustionin kJ mol-1of benzene at constant pressure will be

R=8.314 JK-1 mol-1

Options:

Answer:
A
Solution:

C6H6l+152O2g6CO2g+3H2O(I)    ∴  ng= -32

Use, ΔH=ΔU+ΔngRT

=-3263.5×103-32×8.314×298×10-3 

 =-3267.6 kJ mol-1

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
2mℹ️ Source: PYQ_2018

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