Find the standard enthalpy of formation of liquid ethanol from the following data.
ΔH_c° (C₂H₅OH, l) = -1367 kJ/mol
ΔH°_f (CO₂, g) = -393.5 kJ/mol
ΔH°_f (H₂O, l) = -285.8 kJ/mol

Question

Find the standard enthalpy of formation of liquid ethanol from the following data. ΔH c ° (C 2 H 5 OH, l) = -1367 kJ/mol ΔH° f (CO 2 , g) = -393.5 kJ/mol ΔH° f (H 2 O, l) = -285.8 kJ/mol

TestHub · Accepted Answer

Combustion: C 2 H 5 OH + 3O 2 → 2CO 2 + 3H 2 O. ΔH c = [2(-393.5) + 3(-285.8)] - ΔH f (C 2 H 5 OH). -1367 = -787 - 857.4 - ΔH f . ΔH f = -1644.4 + 1367 = -277.4 kJ/mol. Answer: (C).

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