The enthalpy of combustion of 2 moles of benzene at 2 7 ∘ C differs from the value determined in bomb calorimeter by

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ChemistryThermochemistryEnthalpy of ReactionHard2 minPYQ_2013

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The enthalpy of combustion of 2 moles of benzene at $2 7^{\circ} C$ differs from the value determined in bomb calorimeter by

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By bomb calorimeter we get $Δ E$ . $2 C_{6} H_{6} (l) + 15 O_{2} (g) ⟶ 12 CO_{2} (g) + 6 H_{2} O (1) Δ H - Δ E = Δ nRT = (12 - 15) \times 8.314 \times 300 = - 7.483 kJ$

Stream:BITSATSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2013

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