Chemistry - Surface Chemistry Question with Solution | TestHub

ChemistrySurface ChemistryGeneralEasy2 minPYQ_2020

ChemistryEasynumerical

Graph between $\log (\frac{x}{m})$ and log P is straight line at angle of $45 °$ with the intercept of 0.6020.

The extent of adsorption $(\frac{x}{m})$ at a pressure of 1 atm is

Answer:

4.00

Solution:

$\log (\frac{x}{m}) = \log K + \frac{1}{n} \log P$
$= 0.602 + 1 \log 1$
= 0.602
So $\frac{x}{m} = 4$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Surface ChemistrySubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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